How to Generate UUID in Scala

How to Generate a UUID in Scala

The idiomatic way to generate a UUID in Scala is UUID.randomUUID() via Java interop — Scala has no separate UUID type of its own, so you call the JVM's java.util.UUID class directly. Assign the result to a val and let Scala's type inference handle the rest. The php uuid page covers UUID v3, v4, and v5 generation with the ramsey/uuid package in PHP projects.

Main.scala

import java.util.UUID

val myUuid: UUID = UUID.randomUUID()
println(myUuid)
// Output: 550e8400-e29b-41d4-a716-446655440000

Explanation

import java.util.UUID pulls in the JVM's UUID class — no extra library and no build.sbt dependency required.
UUID.randomUUID() generates a random UUID (version 4) backed by a cryptographically secure random number generator.
val myUuid: UUID = ... shows idiomatic Scala style — an immutable val with an explicit type annotation, though val myUuid = UUID.randomUUID() works identically since Scala infers the type on its own.
println(myUuid) implicitly calls toString, producing the standard 36-character hyphenated format.

Convert a String to a UUID in Scala

Parsing a UUID string in Scala uses the same UUID.fromString() method as Java, which throws an IllegalArgumentException on malformed input rather than returning a safe result. The python uuid generator guide shows how to convert between UUID strings, bytes, and integers for database storage.

Main.scala

import java.util.UUID
import scala.util.Try

val str = "550e8400-e29b-41d4-a716-446655440000"

// Convert the exception-throwing Java API into a safe Option
val maybeUuid: Option[UUID] = Try(UUID.fromString(str)).toOption

maybeUuid match {
  case Some(uuid) => println(s"Valid UUID: $uuid")
  case None       => println("Invalid UUID string")
}

Explanation

UUID.fromString(str) parses a standard 36-character UUID string; called directly it throws IllegalArgumentException on invalid input, exactly like in Java.
import scala.util.Try wraps that exception-throwing call — Try(...) catches the exception and turns it into a Success or Failure.
.toOption converts the Try into Option[UUID] — Some(uuid) on success, None on failure — so callers pattern-match instead of catching exceptions.
This Try(...).toOption pattern is the idiomatic functional-Scala way to make any throwing Java API safe to call.

Other Options for Generating UUIDs in Scala

java.util.UUID has no native support for UUID version 7, the newer time-sortable format many databases now prefer for primary keys. Since Scala compiles to the JVM, projects that need v7 identifiers reach for the same options available to any Java codebase.

build.sbt

libraryDependencies += "com.github.f4b6a3" % "uuid-creator" % "6.0.0"

Main.scala

import com.github.f4b6a3.uuid.UuidCreator

// Version 7 - Unix timestamp + random, sortable and index-friendly
val uuidV7 = UuidCreator.getTimeOrderedEpoch()
println(uuidV7)

Explanation

uuid-creator (group id com.github.f4b6a3) is a JVM library that adds v6, v7, and v8 support on top of java.util.UUID — being pure Java, it works identically when called from Scala.
UuidCreator.getTimeOrderedEpoch() generates a version 7 UUID: a Unix millisecond timestamp in the most significant bits followed by random bits, so IDs sort chronologically.
The returned value is a standard java.util.UUID, so it interoperates with any Scala or Java code that already expects one.
Teams that can't add a dependency implement RFC 9562's v7 layout manually — timestamp bits plus SecureRandom — though a maintained library is less error-prone.

Generate UUID in Scala

How to Generate a UUID in Scala

Explanation

Convert a String to a UUID in Scala

Explanation

Other Options for Generating UUIDs in Scala

Explanation

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